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7x^2+7x-2=8
We move all terms to the left:
7x^2+7x-2-(8)=0
We add all the numbers together, and all the variables
7x^2+7x-10=0
a = 7; b = 7; c = -10;
Δ = b2-4ac
Δ = 72-4·7·(-10)
Δ = 329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{329}}{2*7}=\frac{-7-\sqrt{329}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{329}}{2*7}=\frac{-7+\sqrt{329}}{14} $
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